SOAR Winter 2002
Homework Four
These homework problems are meant to expand your understanding of what
goes on during class. Any you turn in will be graded and returned to
you. Answers may or may not be posted on the web, depending on demand.
- The one part of Lagrange's theorem we didn't prove is the following
lemma:
Suppose H is a subgroup of a finite group G. Then, for any
element g of G, the order of gH equals the order of H.
Let's prove this as follows: first, notice that |gH|
<=
|H|. Next,
show that |gH| >= |H| by showing that one can't have gh1 = gh2
for two distinct elements h1 and h2 of H.
(Sorry, I've used "<=" and ">=" as short-hand for "less than or
equal to" and "greater than or equal to" due to local font
problems.)
-
Complete a Cayley table (that is, a multiplication table) for
D3 and D4, the sets of symmetries of an equilateral triangle and
square. Use the notation that Dn = {1,r,...,rn-1,m,mr,...,mrn-1}, where r is a minimal
counterclockwise rotation and m is a mirror reflection, as in
class. (This is mostly so you'll have these handy for the next two
problems.)
-
Consider the element m in D3. We say that an element y in D3
is conjugate with m if y=x-1mx for some x in D3. So
mr2 is conjugate with m since r-1mr = mr2.
- Find all elements in D3 that are conjugate with m. We call
this set of elements the conjugacy class of m.
-
Find all other conjugacy classes in D3.
- Do any of your conjugacy classes intersect?
-
Does any element not belong to a conjugacy class.
-
Find all the conjugacy classes of D4. Can you determine the
conjugacy classes of Dn?
-
Prove the following facts for any group, G, and elements x, y and
z in G.
- If x is an element of G then x is conjugate with itself.
-
If x and y are conjugate, then y and x are conjugate.
-
If x and y are conjugate and y and z are conjugate then x
and z are conjugate.
These properties are called the reflexive, symmetric and
transitive properties. Any relation, such as conjugacy, which
possesses these properties is said to be an equivalence relation.
-
Write a short computer program to determine all possible vertex
types. Recall that a vertex type is an integer solution
{n1,n2, ... ,nk} of the equation
|
|
n1 - 2
n1
|
+ ... + |
nk - 2
nk
|
= 2 |
|
or, equivalently,
|
|
( (
|
1
2
|
- |
1
n1
|
) )
|
+ ... + |
( (
|
1
2
|
- |
1
nk
|
) )
|
= 1. |
|
(Please excuse the kludged parentheses.)
(The nj are all at least 3, and may repeat values.) You may
assume what we proved in class: there are no solutions with any n
over 42.
These problems are also available as a PDF file.
Course Web Page