SOAR Winter 2002
Homework Six
These homework problems are meant to expand your understanding of what
goes on during class. Any you turn in will be graded and returned to
you. Answers may or may not be posted on the web, depending on demand.
- What is the highest order shuffle of 52 cards. The
formulation of this problem worked out in class, is: find a collection
of positive integers
so that
and
is as large as possible. Feel free to use a computer.
- One fact we did not prove in class is that the order of
(the
even permutations in
) is
, or precisely half the order of
. Write down (a) the
elements of
and (b) the
elements of
. Don't forget the identity!
- Consider the element
in
. We say that an element
is conjugate with
if
for some
. For example,
is conjugate to
since
.
- Prove that if
then
and
for any positive integer
. That is, show
that if
, then
and
.
(Here ``
'' means ``
divides
.'')
- Prove that if
and
, then
. Another way of seeing this is that this means
and
for some integers
and
. You want to
show that
for some integer
.
- Compute (a)
and (b)
. Here is an
extended hint, using as an example the computation of
. We'll compute various powers of
:
Next we write
as
, so
. Working modulo 7, we have
- Show that not all the
are cyclic by showing that
is
isomorphic to
.
- Find all elements in
that are conjugate with
. We call
this set of elements the conjugacy class of
.
- Find all other conjugacy classes in
.
- Do any of your conjugacy classes intersect?
- Does any element not belong to a conjugacy class?
- In this problem, we derive a formula for the Euler
-function
(also known as the totient function). Recall that this is
defined as
the number of integers with and
  |
|
- Prove that for a prime
,
.
(Hint: what are the integers
that have a common factor
with
?)
- (Hard, and I recommend you skip this part and just assume this for
part (c).)
Prove that
is multiplicative. That is, if
then
.
- Derive a formula for
. Your answer should involve
the prime factorization of
.
- What is
?
- Part (b) of the previous problem actually follows from the following
more general version of the Chinese Remainder Theorem than in the
previous homework. (This is with only two equations, but the general
form is with an arbitary number.) We'll prove that, given two
relatively prime integers
and
and elements
and
, there is a unique
such that
(This means that order of
is the product of the orders of
and
, which implies part (b) of the previous problem.)
Let
, where
is the inverse of
in
and
is the inverse of
in
.
- Show that
satisfies the equations above.
- Show that
is an element of
. That is, show that
is
relatively prime to
. (Hint: show that
,
, and
are
all elements of
, hence
is as well. This means that
is relatively prime to
. Do something similar with the
other term.)
- Show that
is unique in
. That is, if
is another
solution, show that
must be an integer multiple of
.
(Hint: we know that
and
. What
does this mean about
,
, and
?)
These problems are also available as a PDF file.
Course Web Page